Doubles
2019 Kiskút Open
Champions	Irina Bara Maryna Zanevska
Runners-up	Akgul Amanmuradova Elena Bogdan
Score	3–6, 6–2, [10–8]

This was the first edition of the tournament.^[1]

Irina Bara and Maryna Zanevska won the title, defeating Akgul Amanmuradova and Elena Bogdan in the final, 3–6, 6–2, [10–8].

Seeds

Draw

Draw

	First round							Quarterfinals							Semifinals							Final
	1	G García Pérez F Stollár	3	0r
		I Bara M Zanevska	6	1					I Bara M Zanevska	6	6
		RL Jani P Ormaechea	5	6	[10]				RL Jani P Ormaechea	2	3
		M Chwalińska A Nagy	7	3	[7]											I Bara M Zanevska	77	6
	3	N Dascălu D Kovinić	w/o												3	N Dascălu D Kovinić	63	1
		V Juhászová M Klaffner						3	N Dascălu D Kovinić	6	6
		A Bondár R Šramková	0	6	[10]				A Bondár R Šramková	4	2
		G Cé S Waltert	6	4	[8]																		I Bara M Zanevska	3	6	[10]
		M Chernyshova C Škamlová	w/o																			4	A Amanmuradova E Bogdan	6	2	[8]
	WC	Á Bukta T Pereira							M Chernyshova C Škamlová	2	64
	WC	B Békefi D Drahota-Szabó	3	4				4	A Amanmuradova E Bogdan	6	77
	4	A Amanmuradova E Bogdan	6	6											4	A Amanmuradova E Bogdan	2	6	[10]
		M Bulgaru IG Ghioroaie	6	6											2	A Anshba A Dețiuc	6	4	[4]
		J Marková D Seguel	4	2					M Bulgaru IG Ghioroaie	2	3
		N Potočnik N Radišič	4	3				2	A Anshba A Dețiuc	6	6
	2	A Anshba A Dețiuc	6	6

References

• Main Draw